GATE AG 2026 • Q47 MSQ • 2 Marks

Section 7: Dairy and Food Engineering

Unit Operations in Dairy and Food Engineering

Subtopic: Pasteurization

Question Statement:

Pasteurisation of milk can be carried out either at 91 °C for 3 s or at 73 °C for 30 s to inactivate vegetative cells of microorganism(s). The sterilisation value is 10 in both the cases. Thermal death time constant (z value) for reference temperatures of 73 °C and 91 °C, in °C, is nearest to -type split: MCQ — 48 questions; NAT — 17 questions (no MSQ in this paper). Farm Power and Soil & Water Conservation Engineering jointly carry 34 marks — the highest-yield pair. Within Farm Power, Tractors and Power Tillers alone contributed 5 questions (traction theory, ergonomics/noise, final drives, steering hydraulics). Hydrology (Q.25, 58, 59) and Fluid Mechanics — flow in open channels (Q.21, 60) dominated Section 4. Engineering Mathematics stayed formula-direct: Linear Algebra (2), Differential Equations (2), Numerical Methods (2), Calculus (1), Vector Calculus (1), Probability and Statistics (1). Several 1-mark questions (Q.21, Q.28, Q.29) deliberately contained redundant data. Recognising the governing definition — rather than computing with every number given — was the real test. Three high-value NAT questions demanded a non-obvious refinement of the standard formula: Q.54 (Taborek’s kingpin torque relation), Q.59 (Snyder’s duration correction) and Q.62 (riser projection deducted from bench width). Solving with the basic formula alone lands outside the official range in each case.

Options:

  • (A) 18.0
  • (B) 1.8
  • (C) 9.0
  • (D) 0.9

Official Answer Key:

A, C

Step-by-Step Solution & Explanation

The z value is the temperature increase required to reduce the thermal death time by a factor of ten. Since both processes achieve the same lethality (sterilisation value 10), the thermal death time relationship applies: log(t₁/t₂) = (T₂ − T₁)/z Substituting t₁ = 30 s at T₁ = 73 °C and t₂ = 3 s at T₂ = 91 °C: log(30/3) = (91 − 73)/z log(10) = 18/z 1 = 18/z z = 18 °C Interpretation: raising the process temperature by 18 °C cuts the required holding time to one-tenth — exactly what the data show (30 s → 3 s for an 18 °C rise). APPENDIX A — CONSOLIDATED OFFICIAL ANSWER KEY APPENDIX B — SECTION-WISE WEIGHTAGE ANALYSIS

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