A 4WD tractor has equal front/rear tread = 1.25 m; CG height = 0.85 m. The tractor overturns during turning at 18 km/h. Neglecting frictional forces on the wheels, find the turning radius (m). (Rounded to 2 decimal places)
Official Answer Key:
3.35 to 3.55
Step-by-Step Solution & Explanation
Overturning occurs when the centrifugal-force overturning moment equals the restoring (weight) moment: (mv²/R)×h_cg = mg×(tread/2). So R = v²×h_cg/[g×(tread/2)]. v = 18 km/h = 5.0 m/s. R = 5.0²×0.85/(9.81×0.625) = 21.25/6.131 = 3.47 m.
Practice This in Real CBT Exam Interface
Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.