GATE AG 2025 • Q30 NAT • 1 Mark

Section 3: Farm Power

Tractors and Power Tillers

Subtopic: Steering and hydraulic control systems used in tractors

Question Statement:

Front-wheel pivot points of a 2WD tractor are 1.2 m apart. Turning on flat concrete, inner wheel steering angle = 50°, outer wheel steering angle = 35°. For turning without front-wheel skid, find the wheelbase (m). (Rounded to 2 decimal places)

Official Answer Key:

1.70 to 2.40

Step-by-Step Solution & Explanation

Correct (Ackermann) steering condition: cot(outer angle) − cot(inner angle) = track/wheelbase. Wheelbase = track/[cot(35°) − cot(50°)] = 1.2/[1.4281 − 0.8391] = 1.2/0.5890 = 2.04 m.

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