Six persons P, Q, R, S, T and U are sitting around a circular table facing the center not necessarily in the same order. Consider the following statements:
• P sits next to S and T.
• Q sits diametrically opposite to P.
• The shortest distance between S and R is equal to the shortest distance between T and U.
Based on the above statements, Q is a neighbor of
Options:
(A) U and S
(B) R and T
(C) R and U
(D) P and S
Official Answer Key:
C
Step-by-Step Solution & Explanation
• Number the six circular seats 1 to 6. Since P sits next to both S and T, place P at seat 1, with S at seat 6 and T at seat 2.
• Q sits diametrically opposite P; with 6 seats, the opposite seat to seat 1 is seat 4. So Q is at seat 4.
• Remaining seats 3 and 5 must be occupied by R and U (in either order).
• Check the distance condition (shortest S–R = shortest T–U): R=3,U=5 gives distance(S6,R3)=3=distance(T2,U5)=3 — satisfied. R=5,U=3 gives distance(S6,R5)=1=distance(T2,U3)=1 — also satisfied.
• In both valid arrangements, seats 3 and 5 (Q's two neighbours) are occupied by R and U. So Q's neighbours are always R and U.
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