The crank radius and connecting rod length of an IC engine are 250 mm and 1000 mm, respectively. If the crank turns 100º from the head dead centre and the net force acting on the piston along its direction of motion is 35 kN, the turning moment of the crank shaft at that instant in kN m is ___________. [round off to two decimal places]
Official Answer Key:
8.00 to 8.50
Step-by-Step Solution & Explanation
• n=l/r=4; T=F·r[sinθ + sin2θ/(2√(n²−sin²θ))]
• sin100°=0.98481, sin200°=−0.34202, √(16−0.96985)=3.8769
• Bracket = 0.98481−0.04410 = 0.94071; T = 35×0.25×0.94071 = 8.23 kN·m
Computed value: 8.23 kN·m (within official range 8.00–8.50)
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