Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses
Question Statement:
A tractor operated 12 × 60 cm boom sprayer had an overlap of 30 cm between the successive passes during field operation at an average speed of 4.2 km h⁻¹. A total time loss of 7.5 min ha⁻¹ was observed during turnings. Assuming no overlap of spray material between adjacent nozzles, the field efficiency of the sprayer in per cent is __________. [round off to two decimal places]
Official Answer Key:
69.00 to 71.00
Step-by-Step Solution & Explanation
• Nominal width = 12×0.6 = 7.2m; effective width = 7.2−0.3 = 6.9m.
• Theoretical field capacity = 7.2×4.2/10 = 3.024 ha/h → 19.84 min/ha. Effective field capacity = 6.9×4.2/10 = 2.898 ha/h → 20.70 min/ha (productive).
• Actual time/ha = 20.70+7.5 = 28.20 min/ha. Field efficiency = 19.84/28.20×100 = 70.35%.
Computed value: 70.35% (within official range 69.00–71.00)
Practice This in Real CBT Exam Interface
Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.