GATE AG 2020 • Q52 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: I.C. engine systems – fuel, cooling, lubrication, ignition, electrical, intake and exhaust

Question Statement:

A tractor's diesel engine cooling system rejects 0.58 kW of heat per kW of brake power; it requires 0.16 L/s of water per kW of heat rejection to maintain a 6 °C temperature drop across the radiator. If the engine develops 45 kW brake power, find the required water flow rate in the radiator (L/s). (Rounded to 2 decimal places)

Official Answer Key:

4.16 to 4.18

Step-by-Step Solution & Explanation

Heat rejected = 0.58×45 = 26.1 kW. Water flow rate = 0.16 L/s per kW × 26.1 kW = 4.176 ≈ 4.18 L/s.

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