A 2WD tractor, total weight 25 kN, wheelbase 2.2 m, CG 0.7 m ahead of the rear axle. A steady horizontal pull is applied at drawbar hitch height 0.5 m such that front-axle weight becomes 20% of static weight. Find the coefficient of net traction. (Rounded to 2 decimal places)
Official Answer Key:
0.64 to 0.66
Step-by-Step Solution & Explanation
Static front weight Wf = W×a/L = 25×0.7/2.2 = 7.9545 kN (a = distance CG–rear axle). Dynamic front weight Wf,dyn = 0.20×25 = 5.0 kN. Using weight transfer: Wf,dyn = (W×a − P×h)/L ⇒ 5.0 = (17.5 − 0.5P)/2.2 ⇒ P = 13.0 kN. Dynamic rear-wheel (drive-wheel) weight = 25 − 5.0 = 20.0 kN. Coefficient of net traction = P/Wr,dyn = 13.0/20.0 = 0.65.
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