GATE AG 2020 • Q33 NAT • 1 Mark

Section 6: Agricultural Process Engineering

Evaporation and Drying

Subtopic: Concentration and drying of liquid foods – evaporators, tray, drum and spray dryers

Question Statement:

Fresh tomato juice (6% w/w total solids) enters a single-effect evaporator at 500 kg/h to be concentrated to 36% w/w solids. Find the rate of water removal (kg/h). (Rounded to 1 decimal place)

Official Answer Key:

416.0 to 418.0

Step-by-Step Solution & Explanation

By overall solids balance, the concentrated-product flow rate = Feed×(C1/C2) = 500×(6/36) = 83.33 kg/h. Water removed = Feed − Concentrate = 500 − 83.33 = 416.7 kg/h.

Practice This in Real CBT Exam Interface

Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.

Launch CBT Mock Test