Subtopic: Mean, median, mode and standard deviation
Question Statement:
Probability and Statistics: Mean, median, mode and standard deviation; random variables; Poisson, normal and binomial distributions; correlation and regression analysis.
The mean absolute deviation about the median for the data 3, 9, 5, 3, 12, 10, 18, 4, 7, 19, 21 (rounded to 2 decimals) is ______.
Official Answer Key:
5.26 to 5.28
Step-by-Step Solution & Explanation
n = 11 (odd). Sorted data: 3, 3, 4, 5, 7, 9, 10, 12, 18, 19, 21. Median (6th value) = 9.
Absolute deviations from 9: |3-9|=6, |9-9|=0, |5-9|=4, |3-9|=6, |12-9|=3, |10-9|=1, |18-9|=9, |4-9|=5, |7-9|=2, |19-9|=10, |21-9|=12.
Sum = 6+0+4+6+3+1+9+5+2+10+12 = 58.
MAD = 58/11 = 5.2727 ≈ 5.27. Answer: within range 5.26–5.28.
Section 2 — Farm Machinery
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