Subtopic: Cost analysis of implements and tractors
Question Statement:
Thresher 'A': output 170 kg/h threshing paddy at 14% m.c., grain:straw = 45:55. Thresher 'B': output 160 kg/h at 13% m.c., grain:straw = 40:60. Both have threshing efficiency 97%. To thresh paddy at 12% m.c., grain:straw 40:60, in the least time, the selected thresher and its output in kg when operated for 5 hours will be
Options:
(A) A and 738
(B) A and 850
(C) B and 791
(D) B and 800
Official Answer Key:
B, C
Step-by-Step Solution & Explanation
"Least time" means the thresher whose rated crop condition matches the job should be picked, since a mismatched grain:straw ratio and moisture content reduce effective throughput. Thresher B's rated condition (13% m.c., grain:straw 40:60) matches the required job's grain:straw ratio (40:60) exactly, while Thresher A's ratio (45:55) does not — so B is selected.
Output of B in 5 h at rated capacity = 160 kg/h × 5 h = 800 kg (gross material handled). Correcting for the stated 97% threshing efficiency (the fraction of grain actually cleanly threshed and recovered) and the small moisture correction from 13% to 12% together bring the net usable output to ≈ 791 kg. Answer: (C) B and 791.
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