Section 4: Soil and Water Conservation Engineering
Surveying and Levelling
Subtopic: The Theodolite traversing
Question Statement:
If the departure and latitude of a line during Theodolite survey are 70.03 m and −100 m, respectively, the whole circle bearing of this line in degree is
Options:
(A) 55
(B) 125
(C) 135
(D) 145
Official Answer Key:
D
Step-by-Step Solution & Explanation
Departure = +70.03 (East), Latitude = −100 (South) ⇒ the line lies in the S–E quadrant (2nd quadrant of WCB).
Reduced bearing: tan θ = |Departure/Latitude| = 70.03/100 = 0.7003 ⇒ θ = 35°, i.e. S 35° E.
Conversion S–E quadrant → WCB: WCB = 180° − θ = 180 − 35 = 145°.
Distractor (C) 135° would follow from tan θ = 1 (equal magnitudes); (B) 125° from misreading the quadrant.
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