Subtopic: Processing of seeds, spices, fruits and vegetables
Question Statement:
India’s annual paddy production is 160 million ton (clean paddy basis). Average husk content of paddy is 22.4% and milled rice yield is 70%. Considering 18% oil content in bran fraction and calorific value of 12 MJ kg⁻¹ of husk, the oil potential of bran and energy potential of husk will respectively be
Options:
(A) 2.19×10⁶ ton; 430080×10¹² J
(B) 2.19×10⁶ ton; 210450×10¹² J
(C) 4.76×10⁶ ton; 210450×10¹² J
(D) 4.76×10⁶ ton; 430080×10¹² J
Official Answer Key:
A
Step-by-Step Solution & Explanation
• Husk mass = 22.4% of 160 Mt = 35.84 Mt (million ton).
• Milled rice mass = 70% of 160 Mt = 112 Mt.
• By mass balance, bran (the remaining fraction) = 160 – 35.84 – 112 = 12.16 Mt.
• Oil potential of bran = 18% of bran mass = 0.18 × 12.16×10⁶ ton = 2.19×10⁶ ton.
• Energy potential of husk = husk mass × calorific value = 35.84×10⁹ kg × 12×10⁶ J/kg = 430.08×10¹⁵ J = 430080×10¹² J.
• Final Answer: (A)
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