Subtopic: Psychrometry – properties of air-water vapour mixture
Question Statement:
An air – water vapour mixture is at 35°C and normal atmospheric pressure with absolute humidity of 0.02 kg water vapour kg⁻¹ dry air. Its humid volume in m³ kg⁻¹ dry air is ______
Official Answer Key:
0.89 to 0.91
Step-by-Step Solution & Explanation
Humid volume (standard psychrometric relation): v_H = (2.83×10⁻³ + 4.56×10⁻³×H)×T(K), where H is the absolute humidity and T is the absolute temperature. T = 35+273 = 308 K. v_H = (2.83×10⁻³ + 4.56×10⁻³×0.02)×308 = (2.83×10⁻³+0.0000912)×308 = 0.0029212×308 = 0.8997 ≈ 0.90 m³/kg dry air, within the accepted band 0.89–0.91.
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