Subtopic: Measurement of force, stress, torque, speed, displacement and acceleration on machine elements – shafts, couplings, keys, bearings and knuckle joints
Question Statement:
A force of 8.0 kN is applied perpendicularly to the axis of a crankpin having circular cross-sectional area. The allowable shear stress of the crankpin material is 40.0 N mm⁻². If the crankpin fails under double shear, the design diameter of the crankpin in mm is ______
Official Answer Key:
11.0 to 11.5
Step-by-Step Solution & Explanation
For double shear, the applied force is resisted by two shear planes: F = 2×τ×A, so A = F/(2τ) = 8000/(2×40) = 100 mm². Since A = πd²/4, d = √(4A/π) = √(400/π) = 11.28 mm, within the accepted band 11.0–11.5.
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