Subtopic: Functional requirements, principles of working, construction and operation of manual, animal, tractor and renewable energy operated equipment for tillage, sowing, planting, fertilizer application, inter-cultivation, spraying, mowing, chaff cutting, harvesting and threshing
Question Statement:
A two-row horizontal plate potato planter with 0.6 m ridge spacing has 9 cups on each seed plate of 0.4 m diameter. For each revolution of the ground wheel, the seed plate makes half a revolution. The diameter of the ground wheel is 0.5 m. If the planter uses cut tubers each of 25 g mass, the seed rate in kg ha⁻¹ is ____________.
Official Answer Key:
1190 to 1250
Step-by-Step Solution & Explanation
Ground-wheel circumference (forward travel per wheel revolution) = πD = π(0.5) = 1.5708 m.
Seeds dropped per row per wheel revolution = cups × (seed-plate revolutions per wheel rev) = 9 × 0.5 = 4.5.
Seed (in-row) spacing = 1.5708 / 4.5 = 0.34907 m.
Area occupied per seed = row spacing × in-row spacing = 0.6 × 0.34907 = 0.20944 m².
Plants/ha = 10,000 / 0.20944 = 47,746 plants/ha.
Seed rate = 47,746 × 0.025 kg = 1193.6 kg/ha, within the accepted band.
Section 3
Sources of Power
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