GATE AG 2014 • Q14 MCQ • 1 Mark

Section 3: Farm Power

Farm Power

Subtopic: Power efficiencies and measurement, engine performance curves

Question Statement:

The brake power of a four-cylinder engine is 30 kW with all cylinders firing and 20 kW with any one cylinder cut. The mechanical efficiency of the engine in percent is

Options:

  • (A) 60
  • (B) 67
  • (C) 75
  • (D) 83

Official Answer Key:

C

Step-by-Step Solution & Explanation

This is the Morse test principle. With one cylinder cut, the engine still overcomes the same friction, but that cylinder contributes no indicated power; the drop in measured brake power approximates the indicated power of the cut cylinder: IP of one cylinder ≈ BP(all firing) − BP(one cut) = 30 − 20 = 10 kW. Total indicated power (4 identical cylinders) = 4 × 10 = 40 kW. Mechanical efficiency = BP/IP = 30/40 = 75%. Answer: (C).

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