GATE AG 2013 • Q6 MCQ • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses

Question Statement:

During the testing of a spike-tooth type thresher for wheat crop, the throughput and the thresher capacity were found to be 750 kg h⁻¹ and 445 kg h⁻¹, respectively. The grain-straw ratio (grain:straw) of the crop is 1.5:1. Material other than grain (MOG) collected at the main grain outlet is 0.5%. The total grain loss in percentage from all the sources will be

Options:

  • (A) 0.33
  • (B) 0.50
  • (C) 1.11
  • (D) 1.61

Official Answer Key:

D

Step-by-Step Solution & Explanation

Grain fraction of throughput = 1.5/(1.5+1) = 0.6, so total grain entering = 750×0.6 = 450 kg/h. Pure grain actually collected at the main outlet = capacity × (1 − MOG fraction) = 445×(1−0.005) = 442.775 kg/h. Total grain lost (uncollected, from all sources) = 450 − 442.775 = 7.225 kg/h. Loss % = 7.225/450 × 100 = 1.61%. Answer: (D).

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