GATE AG 2013 • Q34 MCQ • 1 Mark

Section 1: Engineering Mathematics

Probability and Statistics

Subtopic: Mean, median, mode and standard deviation

Question Statement:

Box 1 contains 15 balls out of which 3 are red. Box 2 contains 12 balls out of which 4 are red. If one ball is drawn at random from each box simultaneously, the probability of getting at least one red ball is

Options:

  • (A) 0.07
  • (B) 0.47
  • (C) 0.53
  • (D) 0.75

Official Answer Key:

B

Step-by-Step Solution & Explanation

P(no red from Box 1) = 12/15 = 0.80. P(no red from Box 2) = 8/12 = 0.6667. P(no red at all) = 0.80×0.6667 = 0.5333. P(at least one red) = 1 − 0.5333 = 0.4667 ≈ 0.47. Answer: (B).

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