A two-wheel drive tractor pulls an implement that has a draft force of 11.5 kN. The total motion resistance of the tractor is 2.5 kN. Under these circumstances, the slip of the drive wheels is 20%. If the power loss in transmission is 20%, the percentage of power lost in converting engine power into drawbar power is _______________
Official Answer Key:
36
Step-by-Step Solution & Explanation
Power flows from the engine → transmission (loses 20%, i.e., 80% delivered) → drive-wheel/tyre-soil interface (loses further to slip, effective travel speed reduced by factor (1−slip)=0.80). Fraction of engine power that reaches the drawbar = (1−0.20)×(1−0.20) = 0.80×0.80 = 0.64.
Percentage of power LOST = (1−0.64)×100 = 36%.
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