Subtopic: Bio-fuels and their use in farm mechanization
Question Statement:
A diesel engine in dual-fuel mode (diesel pilot + producer gas primary) produces 3.5 kW at rated speed, coupled to a generator. Diesel consumed 460 mL/h, producer gas consumed 12.5 m³/h. Calorific values: diesel 35280 kJ/L (i.e., per litre), producer gas 3.97 MJ/m³. The brake thermal efficiency of the engine, in %, is:
Options:
(A) 17.19
(B) 19.13
(C) 22.79
(D) 25.32
Official Answer Key:
B
Step-by-Step Solution & Explanation
Energy input from diesel = 0.460 L/h × 35280 kJ/L = 16,228.8 kJ/h. Energy input from producer gas = 12.5 m³/h × 3970 kJ/m³ = 49,625 kJ/h. Total input = 65,853.8 kJ/h = 18.29 kW. Brake thermal efficiency = brake power/input power = 3.5/18.29 = 0.1913 = 19.13%. Answer: B.
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