Subtopic: Power transmission systems – gear trains, differential, final drives and power take-off
Question Statement:
A tractor PTO-driven stationary peg-tooth wheat thresher operating at a cylinder speed of 540 rpm requires a torque of 250 Nm at the PTO. The minimum net engine power required, in kW, is:
Official Answer Key:
15 to 17
Step-by-Step Solution & Explanation
PTO power = 2πNT/60 = 2π × 540 × 250 / 60 = 14.14 kW. Since 'engine power' must exceed the delivered PTO power by the transmission-train losses (clutch, gearbox, PTO shaft, typically ~90–92% efficient), minimum net engine power = 14.14/0.90 ≈ 15.7 kW, which lies in the official accepted range of 15–17 kW. Answer: 15–17 kW.
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