Subtopic: Drying and milling of cereals, pulses and oilseeds
Question Statement:
300 kg of parboiled and wet paddy having an initial moisture content of 28% (dry basis) was dried in a batch type dryer. During drying operation, grain sample was drawn at regular time intervals to measure its moisture content (dry basis). It was found that the moisture content of the grain borne a linear relationship with drying time till 30 minutes of drying operation at which moisture content was measured to be 20%. The drying rate (kg h⁻¹) during this interval was
Options:
(A) 22.3
(B) 37.5
(C) 41.7
(D) 48.1
Official Answer Key:
B
Step-by-Step Solution & Explanation
Dry-matter mass (constant throughout drying) = wet mass/(1+MC_db initial) = 300/(1+0.28) = 234.375 kg. Water present initially = 300 − 234.375 = 65.625 kg. Water present at t=30 min (MC_db=0.20) = 234.375×0.20 = 46.875 kg. Water removed in 30 min = 65.625 − 46.875 = 18.75 kg. Drying rate = 18.75 kg / 0.5 h = 37.5 kg/h, matching option (B).
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