GATE AG 2011 • Q36 MCQ • 2 Marks

Section 4: Soil and Water Conservation Engineering

Soil Mechanics

Subtopic: Permeability and seepage analysis

Question Statement:

In a falling head permeameter test, the initial head is 0.30 m. The head drops to 0.10 m in 40 min. The permeability of a soil sample, 0.06 m high and 50 × 10⁻⁴ m² in cross-sectional area, is found to be 1.0 × 10⁻⁶ m s⁻¹. The size of the stand pipe in m² is

Options:

  • (A) 1.82
  • (B) 1.82 × 10⁻¹
  • (C) 1.82 × 10⁻²
  • (D) 1.82 × 10⁻⁴

Official Answer Key:

D

Step-by-Step Solution & Explanation

Falling-head permeability formula: k = (a·L)/(A·t)·ln(h1/h2), where a = standpipe cross-section, A = 50×10⁻⁴ m² (sample area), L = 0.06 m (sample height), t = 40×60 = 2400 s. Solving for a: a = k·A·t / [L·ln(h1/h2)] = (1.0×10⁻⁶ × 50×10⁻⁴ × 2400) / (0.06 × ln(3)) = (1.2×10⁻⁵) / (0.06 × 1.0986) = 1.2×10⁻⁵/0.0659 = 1.82×10⁻⁴ m², matching option (D).

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