GATE AG 2010 • Q53 MCQ • 2 Marks

Section 3: Farm Power

Tractors and Power Tillers

Subtopic: Traction theory

Question Statement:

[Linked 52–53] Net traction developed in kN by the rear wheels when fitted with 13.6–28 12PR tyre at normal inflation pressure on a level ground with 15% wheel slip will be

Options:

  • (A) 8.79
  • (B) 9.18
  • (C) 9.78
  • (D) 10.32

Official Answer Key:

A

Step-by-Step Solution & Explanation

Using the Wismer–Luth traction equations with C_n = 78.4 (from Q52) and slip s = 0.15: gross traction coefficient μ = 0.75[1−e^(−0.3·C_n·s)] = 0.75[1−e^(−3.53)] = 0.728. Motion resistance ratio (Q52) = 0.0528. Net traction coefficient = 0.728 − 0.0528 = 0.675. Rear-wheel load = 13.0 kN, so total net traction = 0.675 × 13.0 = 8.78 ≈ 8.79 kN. Section 4 — Soil and Water Conservation Engineering

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