GATE AG 2010 • Q22 MCQ • 1 Mark

Section 7: Dairy and Food Engineering

Preservation of Food

Subtopic: Kinetics of microbial death – pasteurization and sterilization of milk and other liquid foods

Question Statement:

Eight log cycle reduction of Clostridium botulinum having z-value of 9°C needs a process time of 1.5 minute at 121°C. The same degree of reduction at 130°C temperature will require a process time of

Options:

  • (A) 72 s
  • (B) 54 s
  • (C) 18 s
  • (D) 9 s

Official Answer Key:

D

Step-by-Step Solution & Explanation

Thermal death time varies with temperature per: F₂ = F₁ × 10^[−(T₂−T₁)/z]. F₁ = 1.5 min = 90 s at T₁=121°C; T₂=130°C, z=9°C. F₂ = 90 × 10^(−9/9) = 90 × 10⁻¹ = 9 s.

Practice This in Real CBT Exam Interface

Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.

Launch CBT Mock Test