Subtopic: Centrifugal separation of solids, liquids and gases
Question Statement:
Particles having average diameter of 20 μm and particle density of 1000 kg m⁻³ enter a cyclone of 500 mm diameter at a linear velocity of 20 m s⁻¹. The separation factor of the cyclone is
Options:
(A) 136
(B) 163
(C) 316
(D) 613
Official Answer Key:
B
Step-by-Step Solution & Explanation
Separation factor Sf = centrifugal acceleration/gravitational acceleration = v²/(g·Rc), where Rc = cyclone radius = 0.5/2 = 0.25 m. Sf = (20)²/(9.81×0.25) = 400/2.4525 = 163.1, matching option (B). (Particle diameter and density are not required for this ratio — they would be needed to compute a cut-size or collection efficiency, a different quantity.)
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