Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses
Question Statement:
A flywheel type chaff cutter with two cutting knives is having a feeding throat of 0.2 × 0.1 m². The mean chaff length is found to be 20 mm for a flywheel speed of 500 rpm. If the density of the dry fodder is 120 kg m⁻³, the capacity of the chaff cutter in kg h⁻¹ at full load is
Options:
(A) 920
(B) 1440
(C) 2160
(D) 2880
Official Answer Key:
D
Step-by-Step Solution & Explanation
With 2 knives, 2 chaff-lengths of fodder are cut per revolution of the flywheel. Volume of fodder fed per revolution = throat area × chaff length × number of knives = (0.2×0.1) × 0.020 × 2 = 8×10⁻⁴ m³/rev. Volumetric feed rate = 8×10⁻⁴ × 500 rpm × 60 min/h = 24 m³/h. Mass capacity = 24 m³/h × 120 kg/m³ = 2880 kg h⁻¹, matching option (D).
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