Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses
Question Statement:
A tractor sprayer boom is fitted with 20 hollow cone nozzles to achieve an application rate of 200 L ha⁻¹. During a calibration test the nozzle flow rate was found to be 1.25 L min⁻¹, whereas the rated nozzle flow rate of 0.473 L min⁻¹ was available at 275 kPa. If the forward speed of the tractor is 7.5 km h⁻¹, the field capacity of the sprayer in ha h⁻¹ is
Options:
(A) 2.84
(B) 7.00
(C) 7.13
(D) 7.50
Official Answer Key:
D
Step-by-Step Solution & Explanation
Total boom flow = 20 nozzles × 1.25 L/min = 25 L/min = 1500 L/h. At an application rate of 200 L/ha, theoretical field capacity = total flow/application rate = 1500 L/h ÷ 200 L/ha = 7.5 ha/h (this is the effective field capacity implied directly by flow rate and target application rate, independent of separately computing swath width from speed).
Section 3 — Farm Power
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