Subtopic: Mechanics and energy requirement in size reduction of agriculture produce
Question Statement:
A material consisting of 20 mm particles is crushed to an average size of 5 mm and requires 18 kJ kg⁻¹ energy for this size reduction. If other conditions are similar, the energy required (kJ kg⁻¹) to crush the material from 25 mm to 3 mm needs to be calculated. The energy requirement calculated using Rittinger's law will be
Options:
(A) 61.53
(B) 35.16
(C) 16.43
(D) 5.82
Official Answer Key:
B
Step-by-Step Solution & Explanation
Rittinger's law: E = K_R(1/L₂ − 1/L₁). Calibrate K_R from given data: 18 = K_R(1/5−1/20) = K_R×0.15 → K_R = 120. Apply to 25→3 mm: E = 120×(1/3−1/25) = 120×(0.3333−0.04) = 120×0.2933 = 35.2 kJ/kg.
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