Subtopic: Calculation of power, torque, fuel consumption, heat load and power losses
Question Statement:
The torque exerted on the crankshaft of a two stroke engine is given by the equation T (N m) = 450 + 30 sin2θ − 90 cos2θ, where θ is the crank angle displacement from the inner dead centre. If the resisting torque is constant, the power developed by the engine at a speed of 1500 rpm is
Options:
(A) 22.50 kW
(B) 35.30 kW
(C) 70.69 kW
(D) 135.00 kW
Official Answer Key:
C
Step-by-Step Solution & Explanation
Since the sin2θ and cos2θ terms average to zero over a full cycle, mean torque = 450 N·m. Angular speed ω = 2πN/60 = 2π×1500/60 = 157.08 rad/s. Power = T_mean×ω = 450×157.08 = 70,686 W ≈ 70.69 kW.
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