Subtopic: Refrigeration and cold storage basics and applications
Question Statement:
The higher and lower temperatures in a refrigerator working on reverse Carnot cycle are 35 °C and −15 °C respectively. The capacity of the machine is 35.16 kW. The power required will be
Options:
(A) 81.6 kW
(B) 68.1 kW
(C) 8.61 kW
(D) 6.81 kW
Official Answer Key:
D
Step-by-Step Solution & Explanation
Reverse Carnot COP = T_L/(T_H−T_L), with T in Kelvin: T_H=308 K, T_L=258 K. COP = 258/50 = 5.16. Power required = refrigeration capacity/COP = 35.16/5.16 = 6.81 kW.
Practice This in Real CBT Exam Interface
Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.