GATE AG 2008 • Q45 MCQ • 2 Marks

Section 6: Agricultural Process Engineering

Evaporation and Drying

Subtopic: Drying and milling of cereals, pulses and oilseeds

Question Statement:

One hundred kilogram of a food grain is dried from 18% wb to 13% wb moisture content. The total amount of water removed from the grain is

Options:

  • (A) 6.82 kg
  • (B) 6.28 kg
  • (C) 5.75 kg
  • (D) 5.57 kg

Official Answer Key:

C

Step-by-Step Solution & Explanation

Dry matter (constant) = 100×(1−0.18) = 82 kg. Final total mass at 13% wb: Wf = 82/(1−0.13) = 94.25 kg. Water removed = 100 − 94.25 = 5.75 kg.

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