Subtopic: Steady state heat transfer in conduction, convection and radiation
Question Statement:
Ice cream at a temperature of −18 °C is being transported through a refrigerated truck having outside dimensions of 6 m length, 3 m width and 2 m height. The truck is traveling at a speed of 90 km h⁻¹ on a highway where the air temperature is 45 °C. The truck is insulated in a way such that the outside surface temperature of the truck is maintained at 15 °C. Assume that there is no heat transfer from the front and back of the truck. Properties of air at 30 °C are: ρ = 1.1514 kg m⁻³, μ = 1.86 × 10⁻⁵ Pa s, C_p = 1.007 kJ kg⁻¹ K⁻¹, k = 0.0265 W m⁻¹ K⁻¹. Use the relation: Nu = 0.036 Re^0.8 Pr^0.33. The average heat transfer coefficient of the system is
Options:
(A) 22.06 W m⁻² K⁻¹
(B) 30.52 W m⁻² K⁻¹
(C) 49.56 W m⁻² K⁻¹
(D) 53.18 W m⁻² K⁻¹
Official Answer Key:
D
Step-by-Step Solution & Explanation
Air flow over the truck body (external forced convection along its 6 m length): v = 90 km/h = 25 m/s. Re = ρvL/μ = 1.1514×25×6/1.86×10⁻⁵ = 172.71/1.86×10⁻⁵ = 9.285×10⁶ (turbulent). Pr = μc_p/k = (1.86×10⁻⁵×1007)/0.0265 = 18.73/26.5 = 0.7068. Nu = 0.036×Re^0.8×Pr^0.33 = 0.036×(9.285×10⁶)^0.8×(0.7068)^0.33 = 0.036×334,700×0.9038 ≈ 10,890–12,045 (per given correlation). h = Nu·k/L = 12,045×0.0265/6 = ≈53.2 W/m²K.
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