Subtopic: Functional requirements, principles of working, construction and operation of manual, animal, tractor and renewable energy operated equipment for tillage, sowing, planting, fertilizer application, inter-cultivation, spraying, mowing, chaff cutting, harvesting and threshing
Question Statement:
A field sprayer having a boom with 20 nozzles spaced 0.46 m apart is to be designed for a maximum application rate of 750 litre ha⁻¹ at 520 kPa pressure. The forward speed of travel is 6.5 km h⁻¹. Neglect field losses and assume that 10% of the pump output is bypassed. The required pump capacity is
Options:
(A) 67.95 litre min⁻¹
(B) 74.75 litre min⁻¹
(C) 82.22 litre min⁻¹
(D) 83.06 litre min⁻¹
Official Answer Key:
D
Step-by-Step Solution & Explanation
Boom (spray) width = 20×0.46 = 9.2 m. Forward speed = 6.5 km/h = 108.33 m/min. Required nozzle discharge, Q_spray = (application rate × width × speed)/10,000 = (750×9.2×108.33)/10,000 = 74.75 l/min. Since 10% of the pump's output is bypassed (for agitation/relief), pump capacity must be larger: Q_pump = Q_spray/(1−0.10) = 74.75/0.90 = ≈83.06 l/min.
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