Subtopic: Sources of power on the farm – human, animal, mechanical, electrical, wind, solar and biomass
Question Statement:
A flat plate solar collector with an absorber area of 1.0×1.5 m receives a solar flux of 850 W m⁻² on the top cover. The indicated solar flux absorbed in the absorber plate is 600 W m⁻². The ambient temperature is 297 K. The heat loss coefficients of the collector at the side, bottom and top are 0.35, 0.65 and 3.50 W m⁻² K⁻¹ respectively with a collector heat-removal factor of 0.85. The collector fluid temperature is 333 K. Instantaneous collector efficiency is
Options:
(A) 43.80%
(B) 47.40%
(C) 51.53%
(D) 55.76%
Official Answer Key:
A
Step-by-Step Solution & Explanation
Instantaneous efficiency η = Q_u/(I×A), where I=850 W/m² is the incident flux on the top cover, A=1.5 m². η = 558.45/(850×1.5) = 558.45/1275 = 43.80%.
Section 4: Soil and Water Conservation Engineering
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