GATE AG 2007 • Q76 MCQ • 2 Marks

Section 3: Farm Power

Sources of Power

Subtopic: Sources of power on the farm – human, animal, mechanical, electrical, wind, solar and biomass

Question Statement:

A flat plate solar collector with an absorber area of 1.0×1.5 m receives a solar flux of 850 W m⁻² on the top cover. The indicated solar flux absorbed in the absorber plate is 600 W m⁻². The ambient temperature is 297 K. The heat loss coefficients of the collector at the side, bottom and top are 0.35, 0.65 and 3.50 W m⁻² K⁻¹ respectively with a collector heat-removal factor of 0.85. The collector fluid temperature is 333 K. Useful heat gain rate for the collector is

Options:

  • (A) 558.45 W
  • (B) 604.35 W
  • (C) 657.01 W
  • (D) 711.02 W

Official Answer Key:

A

Step-by-Step Solution & Explanation

Overall heat-loss coefficient, U_L = U_side+U_bottom+U_top = 0.35+0.65+3.50 = 4.50 W/m²K. Useful heat gain: Q_u = F_R·A·[S − U_L(T_c−T_a)], S=absorbed flux=600 W/m². Q_u = 0.85×1.5×[600 − 4.50×(333−297)] = 1.275×[600−162] = 1.275×438 = 558.45 W.

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