Section 4: Soil and Water Conservation Engineering
Fluid Mechanics
Subtopic: Ideal and real fluids, properties of fluids
Question Statement:
The left limb of a U-tube manometer is connected to a pipe in which water flows and the right limb containing mercury is open to the atmosphere. The center of the pipe is 200 mm below the level of mercury in the right limb and difference in levels in the two limbs is 300 mm. The pressure in the pipe line is
Options:
(A) 19 kPa
(B) 29 kPa
(C) 39 kPa
(D) 49 kPa
Official Answer Key:
C
Step-by-Step Solution & Explanation
Right-limb mercury level is 200 mm above pipe centre; left-limb (water/mercury interface) level is 300 mm lower than the right, i.e. 100 mm below the pipe centre — so there is 100 mm of water above the interface, pipe-side. Manometer equation: P_pipe + ρ_w·g·(0.100) = ρ_Hg·g·(0.300). P_pipe = 13600×9.81×0.300 − 1000×9.81×0.100 = 40,025 − 981 = ≈39.0 kPa.
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